Monday, February 20, 2023

Acids & Bases

Acids & Bases

A selection of oranges and Toothpaste squeezed out of tube.
Rights: The University of Waikato Te Whare Wānanga o Waikato

Common acids and bases

Citrus fruits contain citric acid. Toothpaste is a weak base. Toothpaste neutralises the acids in foods and protects tooth enamel.

Acids

Acids taste sour – in fact, the German word for acid is sauer. Because acids can damage cells, our stomach needs a special lining to protect it from the hydrochloric acid used to digest our food. We are familiar with some acids – citrus fruits, tomatoes and vinegar are acidic.

Pictogram warns that a substance is corrosive and can harm.
Rights: Public domain

Danger – corrosive materials

This pictogram signals that a substance is corrosive and can harm materials and/or skin if contact happens.

Acids react with most metals including magnesium to create hydrogen gas and a salt – there are lots of different types of salts in chemistry. They also react with a group of substances called carbonates to produce carbon dioxide gas, salt and water. Learn about the reactions of calcium carbonate (like limestone) in this article.

Bases

A corrosive substance is one that will damage or destroy other substances with which it comes into contact by means of a chemical reaction.

Bases feel slippery to touch. This is because they can change the structure of proteins. A strong base can cause severe chemical burns because it starts to damage the proteins in your skin. Basic substances are used in many cleaning products.

The simple chemistry

An acid is a substance that produces hydrogen (H+ions when it is added to water. A hydrogen ion is just the proton and no electron. If we look at the formulas of different acids, we can see that they all contain at least one H (hydrogen) – for example:

  • HCl – hydrochloric acid
  • H2SO4 – sulfuric acid
  • HNO3 – nitric acid.

When we put a molecule of acid into water, it breaks apart. The science term for this is that it dissociates. For example hydrochloric acid (HCl) dissociates into hydrogen ions (H+) and chloride anions (Cl-).

The chemical difference between acids and bases is that acids produce hydrogen ions and bases accept hydrogen ions.

base is a substance that neutralises acids. When bases are added to water, they split to form hydroxide ions, written as OH-. We call a base that has been added to water an alkaline solution.

If we look at some formulas for bases, we can see that they all contain hydroxide (OH-) ions – for example:

  • NaOH – sodium hydroxide (caustic soda)
  • NH4OH – solution of ammonia in water
  • Ca(OH)2 – calcium hydroxide (builders’ lime)

If an acid and a base are added together, they react to form water (H2O) and a salt. An example you might be familiar with is brushing your teeth. The acid created from the bacteria on your teeth reacts with the base in your toothpaste. This reaction is called neutralisation.

Identifying and measuring acids and bases

A pH meter measures how acidic or basic a solution is. When we test a substance with a pH meter, we get a number from 0–14. This is a pH scale, and it can be used to compare substances. It is important to know that this scale is logarithmic. This means that a decrease in the pH scale of 1 can result in an increase of 10 times the concentration of hydrogen ions.

Acids have a pH below 7. The more Hions, the more acidic it is and the lower the pH will be. Bases have a pH above 7. pH 7 is said to be neutral – this means there is a balance of H+ and OH- ions. Sometimes, the pH value can be less than 0 for very strong acids or greater than 14 for very strong bases.

The pH scale measures the acidity or alkalinity of a substance.

Friday, July 5, 2019

B.Sc.I Practical Chart


                                    ESTIMATION OF ANILINE

Aim :

Determine the Amount of Aniline solution in kg / dm3

Given :

            Bottle B           :           Na2S2O3 ( 0.1N )

                        Bottle C           :           Brominating Solution ( Approx. 0.1 N )

                        Bottle D           :           Aniline

Procedure :

Back Titration :

            Take exactly 10 ml of Brominating soln in a stoppered bottle and add about 10 ml of Aniline (by pipette) . Add about 3 ml (¼ TT) conc. HCl and about 25 ml (2 TT) dist. water Shake and wait for about 10 min. Then add about 10 ml 10% KI (1 TT). Titrate immediately the liberated iodine against Na2S2O3. Using starch indicator take 3 Readings and call the const. reading as Y ml. Record the observations

BlankTitration :

            Take exactly 10 ml of Brominating soln in a stoppered bottle and add about 3 ml (¼  TT) conc. HCl and add about 25 ml (2 TT) dist. water. Then add about 10 ml 10% KI (1 TT). Titrate the liberated iodine against Na2S2O3. Using starch indicator take 3 Readings and call the const. reading as X ml. Record the observations and do the calculations.


RESULT :

Strength of Aniline in G/L = ............. gms.   

\kg / dm3 of Aniline = ____________.

 



ESTIMATION OF ANILINE

 

Blank Titration                                                           Back Titration

Soln. in Burette : Na2S2O3(0.1 N)                                 Soln. in Burette : Na2S2O3(0.1 N)
Soln. in stoppered Bottle :                                            Soln. in Stoppered Bottle :
10 ml Brominating soln.                                              10 ml Brominating soln. + 10ml Aniline
+ 1/4 T.T. conc. HCl                                                    + 2 TT Dist. H2O + 1/4 TT conc. HCl
+ 2 T.T. Dist. Water                                                     Shake and wait for 10 min + 1 T.T. 10% KI
+ 1 T.T. 10% KI
Indicator : Freshly prepared starch soln. (2 ml)            Indicator : Freshly prepared starch soln. (2 ml)
End Point : Blue to colourless                                      End Point : Blue to white ppt

 

Reaction :

1) KBrO3 + 5KBr + 6 HCl ®                           1) 5 KBr + KBrO3 + 6 HCl =
    3 Br2 + 6 KCl + 3H2O                                       6 KCl + 3H2O + 3 Br2
2) Br2 + 2 KI = 2KBr + I2                                                     NH2                        NH2
3) I2 + 2Na2S2O3 = Na2S4O6 + 2NaI                                                            Br               Br
 

                                                                                    2)            + 3 Br2  =                  ¯ + HBr
 

    
    Br
                                                                                    3) Br2 + 2KI = 2KBr + I2
                                    4) I2 + 2Na2S2O3 = Na2S4O6 + 2NaI

Burette Level
Pilot ml.
Burette Readings
C.B.R. ml.

Burette Level
Pilot ml.
Burette Readings
C.B.R. ml.
I
II
III
I
II
III
Final





X ml.

Final





Y ml
Initial
0
0
0
0

Initial
0
0
0
0
Difference





Difference





Calculations :
X ml of 0.1 N Na2S2O3            º          Total Brominating soln.
Y ml of 0.1 N Na2S2O3                º          Unused Brominating soln.
(X – Y) = V ml of Na2S2O3      º          Used Brominating soln. by 10 ml Aniline

 

From Equations :-

2 Na2S2O3        º          I2          º          Br2       º          C6H5NH2
\6 Na2S2O3     º          3I2        º          3Br2     º          C6H5NH2
\6 Na2S2O3 ,   5H2O              º          C6H5NH2
\6 x 156 gm Na2S2O3 5H2O   º          93 gms of Aniline.
6 x 10,000 ml 0.1 N Na2S2O3 º          93 gms of Aniline.
\V ml of 0.1 N Na2S2O3         º          V x 93 / 60,000 gms of Aniline = ‘g’ gms

G/L of Aniline = ‘g’ x 100 gms.
\kg / dm3 of Aniline = ____________.